Write the polynomial f(x) that meets the given conditions. Degree 3 polynomial with zeros of -2,4i, and -4i.

f(x) = x^3 + 2 x^2 + 16 x + 32

or also

f(x) = k (x^3 + 2 x^2 + 16 x + 32)

Step-by-step explanation:

Given that -2, 4i and - 4i are roots, then the binomial factors to be included are:

(x - - 2) (x - 4i) (x --4i) = (x + 2) (x - 4i) (x + 4i) =

(x + 2 ) (x^2 - x 4i + x 4i - 16 i^2) = (x + 2) (x^2 + 16) =

x^3 + 16 x + 2 x^2 + 32

which in standard form reads:

x^3 + 2 x^2 + 16 x + 32

Also have in mind that the polynomial could also include a constant multiplicative factor "k".

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.