Help please!! Find the equation of a line perpendicular to 5x - 3y = - 2 that contains the point (-4,5). Write the equation in slope
intercept form

Hi I will give explanation figure out the answer from this :D

Step-by-step explanation:

5x-3y=-2

Put equation in slope-intercept form:

-3y=-5x-2

y=5/3x+2/3

So you have the slope; now find perpendicular slope.

perpendicular slope-3/5

Now, put (-4,5) in to y=-3/5x+b

5=-4(-3/5)+b

5=12/5+b

b=13/5

Now, use all the information and put in slope-intercept. Hope it helps! :)