The pilot of an airplane flying at an elevation of 5000 feet sights two towers that are 300 feet apart. If the angle of depression to the tower closer to him is 30, determine the angle of depression to the second tower.

29.2°

Step-by-step explanation:

From diagram (b)

Tan θ= opp/adj

Where θ = 30°

opp = 5000ft

adj = ?

tan 30° = 5000/x

x tan30° = 5000

x = 5000/tan 30

x = 5000/0.577

x = 8665.5ft

From diagram c

tan θ = opp/adj

Where θ = ?

opp = 5000

adj = 300+x

x= 8665.5

tan θ = 5000/300+8665.5

tan θ = 5000/8965.5

tan θ = 0.55769

θ = arch tan 0.55769

θ = 29.147

θ= 29.2°

the correct answer is 5 6 and 7