A ball is thrown from an initial height of 1 meter with an initial upward velocity of 20 m/s. The ball's height h (in meters) after t seconds is given by the following
h = 1+200-512
Find all values of t for which the ball's height is 11 meters.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°

what are the