On a coordinate plane, a curved line, labeled f of x, with minimum values of (negative 1.6, negative 56) and (2, 0), and a maximum value of (0.8, 11.4), crosses the x-axis at (negative 2.5, 0), (0, 0), and (2, 0), and crosses the y-axis at (0, 0). Which intervals show f(x) increasing? Choose two options. [–2.5, –1.6) [–2, –1] (–1.6, 0] [0, 0.8) (0.8, 2)

The correct options are;

(-1.6, 0] [0, 0.8)

Step-by-step explanation:

The given information are;

The minimum values are (-1.6, -56) and (2, 0), and the maximum value is (0.8, 11.4),

The x-intercept are (-2.5, 0), (0, 0), and (2, 0)

The y-intercept (0, 0)

Therefore, given that (-1.6, -56) is a minimum point followed by a x-intercept are  (0, 0), while continuing to a maximum value at (0.8, 11.4),  then between the interval of (-1.6, 0] f(x) is increasing on average

Similarly, given that (0, 0) is an x-intercept and the maximum point is at at (0.8, 11.4) followed by another x-intercept at (2, 0), the function increases across [0, 0.8) on average

The two points are (-1.6, 0] and [0, 0.8)

i am sure it will be 90 degrees.

step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1