Choose one of the formulas, i do not know which one to choose from. Explanation as well please. At the end of week one, a stock had increased in value from $5.75 a share to $7.50 a share. Find the percent of increase at the end of week one to the nearest tenth of a percent. At the end of week two, the same stock had decreased in value from $7.50 to $5.75.Is the percent of decrease at the end of week two the same as the percent of increase at the end of week one?Justify your answer.

First, we will find the increase. I don't think it's any of the 3 formulas listed.

The formula I'll be using is Increase = Increased value - Original value

Let x be increase.

x = $7.50 - $5.75

x = $1.75

We then divide the increase by the original value.

Percent of increase = Increase/Original value

Let x be percent of increase.

x = $1.75/$5.75

x is approximately 0.30437

To turn a decimal into a percent, multiply it by 100.

0.30437 x 100 = 30.437

30.437 can be rounded to 30.4

The percent of increase at the end of week one is 30.4%

We will first need to find the percent of decrease.

The formula will be Decrease = Original value - Decreased value

Let x be decrease

x = $7.50 - $5.75

x = $1.75

We then divide the decrease with the original value.

Percent of decrease = Decrease/Original Value

Let x be percent of decrease

x = $1.75/$5.75

x is approximately 0.30437

To turn a decimal into a percent, multiply it by 100.

0.30437 x 100 = 30.437

30.437 can be rounded to 30.4

The percent of decrease at the end of week one is 30.4%

No because the full percent of increase at the end of week one is 100% + 30.4% so that would be like a 130.4% increase while at the end of week two, it would be 130.4% - 30.4% and that would lead us back to 100%.

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)