The length of a new rectangular playing field is 2 yards longer then double the width. If the perimeter of the rectangular playing field is 322 yards, what are its dimensions?

Step-by-step explanation:

First, we want to take the information we have and turn it into an equation, where x is our unknown dimension. For this problem, it would be better if x was equal to the width.

Let's  write out the equation:

X is the width, 2x + 2 is the length, and we are multiplying both by two since there are two sides of the field. It will all equal to 322, because that is the perimeter.

2*x + 2(2x +2) = 322

Now, let's solve:

2*x + 2(2x + 2) = 322

2x + 4x + 4 = 322

6x + 4 = 322

6x = 318

x = 318 ÷ 6

x = 53

The width is 53 yards. To find the length, we multiply 53 by two and add two.

53 * 2 + 2 = 106 + 2 = 108 yards, as the length

step-by-step explanation:

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