John opened a factory with 11 supervisors and 5 managers on its staff. He plans to hire additional employees at a rate of 2 supervisors per month and
4 managers per month. Eventually, there will be an equal number of each
type of worker in the factory staff. How many of each type will there be?
How long will that take?

It will take 3 months for both types of workers to have the same number, and it will be 17 of each type

Step-by-step explanation:

There are actually 11 supervisors and 5 managers at John's factory.

This makes a difference of 6 people in the staff.

John will hire 2 additional supervisors per month and 4 managers per month.

Since the number of additional managers per month is greater than the additional supervisors per month, both numbers will eventually be the same.

The difference between the number of additional personnel is 4-2=2 per month.

The actual difference is 6, at a rate of 2 per month will take 6/2 = 3 months to be equal.

In 3 months, there will be 11+2*3=17 supervisors.

In 3 months, there will be 5+4*3=17 managers.

It will take 3 months for both types of workers to have the same number, and it will be 17 of each type

how many players are there?

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)