What is the value of min the figure below? In this diagram, AABD ABCD. 8
m
C
A. 136
B. 572
C. 32
Ο Ο Ο
D. V632
E. 147
o
F. 274
HELP

This is equivalent to 2*sqrt(34)

Explanation:

First let's find BD

The three triangles are similar, allowing for the proportion to be set up

AD/BD = BD/DC

9/x = x/8

9*8 = x*x

x^2 = 72

x = sqrt(72)

BD = sqrt(72)

Now we can use the pythagorean theorem. Focus on triangle BDC.

The legs are BD = sqrt(72) and DC = 8. Let's find the hypotenuse

(BD)^2 + (DC)^2 = (BC)^2

(sqrt(72))^2 + (8)^2 = m^2

72 + 64 = m^2

136 = m^2

m^2 = 136

m = sqrt(136)

We can simplify this but your teacher has chosen not to. If you want to simplify, then,

m = sqrt(136)

m = sqrt(4*34)

m = sqrt(4)*sqrt(34)

m = 2*sqrt(34)

idk

step-by-step explanation:

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".