X2 + 4x – 9 Can someone give me step by explanation for this vertex form question and write the equation in vertex form?

6x-9

Step-by-step explanation:

2x+4x=6x

add the -9 at the end

thats all

y=(x+2)^2−13

Step-by-step explanation:

Set the polynomial equal to y to find the vertex form.

y=x^2+4x−9

Complete the square for  x^2+4x−9

Use the form ax^2+bx+c , to find the values of a, b, and c.a=1,b=4,c=−9

Consider the vertex form of a parabola. a(x+d)^2+e

Substitute the values of a and b into the formula d= b/2a.

d= 4/2(1)

Cancel the common factor of 4 and 2.

d=2

Find the value of e using the formula e=c− b2/4a.

e=−13

Substitute the values of a, d, and e into the vertex form a(x+d)^2+e.

(x+2)^2−13

Set y equal to the new right side.

you forgot an image

step-by-step explanation:

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!