Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions: y > 3x + 10

y is less than negative 3 over 4 times x minus 1

Part A: Describe the graph of the system, including shading and the types of lines graphed. Provide a description of the solution area. (6 points)

Part B: Is the point (8, 10) included in the solution area for the system? Justify your answer mathematically

9514 1404 393

  A) The graph is the quadrant of the coordinate plane that lies between the two lines and to the left of the point (-2 14/15, 1 1/5)

  B) no; it does not satisfy either inequality

Step-by-step explanation:

A) The boundary line defined by the first inequality is a dashed line with a slope of 3 and a y-intercept of 10. Shading is above the line (and to its left).

The boundary line defined by the second inequality is a dashed line with a slope of -3/4 and a y-intercept of -1. Shading is below the line (and to its left).

The two lines cross at the 2nd-quadrant point (-2 14/15, 1 1/5). The solution area is the area between the crossing lines and to the left of that point. Neither that point nor any point on either line is part of the solution area.

The solution area is the doubly-shaded area in the attached graph.

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B) The first-quadrant point (8, 10) is not in the solution area, since the solution area is comprised of parts of quadrants 2 and 3 only.

We can see that (8, 10) will not satisfy either inequality:

  10 > 3(8) +10 . . . . not true

  10 < -3/4(8) -1 . . . . not true

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

14

step-by-step explanation:

14 x 3 = 42