The slope-intercept form of the equation of a line that passes through point (–3, 10) is y = 2x + 16. What is the point-slope form of the equation for this line? (A): y -3 = 2 (x +10)

(B): y +3 = 2 (x -10)

(C): y + 10 = 2 (x - 3)

(D): y - 10 = 2 (x + 3)

D

Step-by-step explanation:

the equation would be D bc using the point given u can fill out the equation y-y1=m(x-x1) so it would be y-10=m(x-(-3). then fill in slope and change the (x-(-3) into x+3. The equation is now y-10=2(x+3).

what are the statments

step-by-step explanation:

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4