A box of chocolates contains four milk chocolates and five dark chocolates. You randomly pick a chocolate and eat it. Then you randomly pick another piece. What are the odds that both pieces were milk chocolate?( show explanation)

1/6

Step-by-step explanation:

firstly the question is a probability without replacement because the chocolate are eaten after being picked .

next sum the total chocolate in the bag (4+5)=9

now probability is possible outcome over total outcome.

P(a)and p(b) =p(a)xp(b)

p(a)=4 /9

p(b)=3/8 ... because there will be 3 milk chocolate and 5dark chocolate left

hance P=(4/9)(3/8)

=1/6

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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