Give me 5 different ordered pairs for y = 5 ( x + 2 ).

(1,15)

(2,20)

(3,25)

(-1,5)

(-2,0)

Step-by-step explanation:

all you hve to do is substitute a value of x into the equation and calculate the value of y

eg : when x = 1

y = 5 ( x+2 )

y = 5 ( 1+2 )

y = 15

thus , x= 1 , y = 15

ordered pair: (1,15)

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.