Determine the percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain weight of kg.

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Complete Question

According to one study, brain weights of men are normally distributed with a mean of 1.40 kg and a standard deviation of 0.11 kg.

Determine the percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.40 kg.

88.36%

Step-by-step explanation:

When given random samples, the formula for z score that we use is:

z = (x-μ)/σ/√n

where x is the raw score

μ is the population mean

σ is the population

n is number of random samples

mean = 1.40 kg

Standard deviation = 0.11 kg

n = 3

x = mean brain weights within 0.1 kg of the population mean brain weight of 1.40 kg.

= 0.1kg ± 1.40kg

Hence,

For 1.50kg

z = 1.50 - 1.40/0.11/√3

z = -1.57

Probability value from Z-Table:

P(x = 1.50) = 0.9418

For 1.30kg

z = 1.30 - 1.40/0.11/√3

= -1.57

Probability value from Z-Table

P(x= 1.30) = 0.0582

P(x = 1.50) - P(x= 1.30)

0.9418 - 0.0582

= 0.8836

Converting to percentage,

0.8836 × 100

= 88.36%

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°