A person must score in the upper 2% of the population on an IQ test to qualify for membership in Mensa, the international high –IQ society. There are 110,000 Mensa members in 100 countries throughout the world. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 15, what score must a person have to qualify for Mensa?

Step-by-step explanation:

Upper 2% means , the Z value must be .98

P ( X - k ) = .98

from the chart the value is found to be 2 .07 .

Hence

(X - 100) / 15 = 2.07

X - 100 = 31.05

X = 131.05

The person must score 131.05 in the IQ test .

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure

what chart am i supposed to follow?