A path 5m wide runs along inside a rectangular field. The length of the rectangular field is three times the breadth of the field. if the area of the path is 500m2, then find the length and breadth of the field..

Length = 45m

Breadth = 15m

Step-by-step explanation:

Dimensions of Rectangular field:

Let the breadth (B)=BC = x m

Length (L) = AB = 3x m

width of the road (w) = 5 m

Dimensions of inner rectangle:

length (l) = EF = L-2w

= 3x - 2×5

= (3x-10) m

breadth (b)=EH = B-2w

= (x-10) m

Given ,

Area of the path =500 m²

=> Area of ABCD - Area of EFGH = 500

=> L×B - l×b=500

=> (3x)× x - (3x-10)(x-10)=500

=> 3x²-(3x²-30x-10x+100)=500

=> 3x²-3x²+30x+10x-100=500

=> 40x=500+100

=> 40x = 600

=> x = 600/40

=> x = 15

Therefore,

Length (L) = 3x = 3×15 = 45m

Breadth (B) = x = 15m

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b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.

w'x is 0.

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