A country makes license plates for cars with exactly 4 characters and no spaces. The characters can be any letter A-Z or any number 0-9. If a license plate is made with random characters, what is the probability that the license plate will be "EAHS"? * Captionless Image
1/36
1/58,905
1/1,413,720
1/1,500,625
1/1,679,616

First, we need to know how many possibilities we have in each position.

We know there can go any letter to A - Z (26 possibilities) and any number to 0-9 (10 possibilities).

Now, we can sum the possibilities we have at each position (as there are the same at all):

26 + 10 = 36 possibilities

Now, we know how many possibilities there are for each position and we need to calculate the total one, so, if there are 4 position and each of them has 36 possibilities, we only need to multiply 36 four times, so it's

The result of doing this is 1679616

so, the possibility to get that or any plate is 1/1679616

(23*2)-12=x     x=34

step-by-step explanation:

a

step-by-step explanation: