Find the equation of the tangent line to the curve y= 2x2 + x-1 at the point (5, 54).

y-54=21(x-5) or y=21x-51

Step-by-step explanation:

To find the equation of the tangent line, we first want to find the derivative of the equation.

f(x)=2x²+x-1           [Power Rule]

f'(x)=4x+1

Now that we have the derivative, we use (5,54) to find the slope.

f'(5)=4(5)+1            [multiply]

f'(5)=20+1              [add]

f'(5)=21

With our slope, we can plug it into point-slope form.

y-54=21(x-5)

We can also convert this to slope-intercept form.

y-54=21(x-5)          [distribute]

y-54=21x-105        [add both sides by 54]

y=21x-51

Now, we know the tangent line is y-54=21(x-5) or y=21x-51.

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step-by-step explanation:

step-by-step explanation:

for exempl this   system of equations   y = x - 3

                                                                y = 2x - 5

look   the line : y = x -3     ( red)

                            the line : y = 2x -5 ( bleus)