The expression x3 – 64 can be written as (x)3 – (4)3. what is the factorization of x3 – 64? a3 – b3 = (a – b)(a2 ab b2) (x – 4)(x2 4x 8) (x – 4)(x2 4x 16) (x – 64)(x2 64x 16) (x – 64)(x2 64x 4,096)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."