Given the functions: f(x) = x2 – 9, and g(x) = x3 + 4x² + 8x - 7, find h(x) = f(x) + g(2).
h(x) =
x3 + 5x2 + 80 -16
h(x) = x3 + 3x² + 80 + 2
h(x) = x3 + 5x2 + 8x - 16
h(x)
- 23 - 3x? 8.2 - 2
h(x)
x3 + 3x2 + 8x + 2

h(x) = x² + 24

Step-by-step explanation:

First solve for g(2) in g(x) = x³ + 4x² + 8x - 7 by simply substituting 2 in x variable. The result is 33.

Then get the sum of f(x) and 33 to find h(x).

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

i need more details sorry

step-by-step explanation: