Graph the line that passes through the points (6,4) and (8,8) and determine the equation of the line 30 POINTS AND BRAINLEST

Equation of the line: y= 2x-8

Graph is attached.

Step-by-step explanation:

First, start by inputing the given points into slope equation:

Simplify.

Then, substitute the slope for m in y=mx+b.

y=2x+b

Find b by substituting one of the points for x and y.

4=2(6)+b

Solve for b.

4=12+b

b=-8

Then substitute b into y=2x+b.

y=2x-8

d? maybe

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.