Pleasse helppp Find the line that is perpendicular to f(x) = -1/3x + 8 and when evaluated, f(-2) = 6.

A. f(x) = 3x + 1 B. f(x)=3x+12

Work Shown:

f(x) = (-1/3)x+8 is the same as y = (-1/3)x+8

Compare this to y = mx+b. The slope is m = -1/3

Flip the fraction to get -1/3 turn into -3/1 = -3. Then flip the negative to positive getting m = 3 as the perpendicular slope.

Side note: the original slope and perpendicular slope multiply to -1.

We want this new equation to go through (x,y) = (-2,6) due to the notation f(-2) = 6

So,

y = mx+b

y = 3x+b ... plug in the perpendicular slope

6 = 3(-2)+b ... plug in the given point's coordinates

6 = -6+b

6+6 = b ... add 6 to both sides

12 = b

b = 12

Therefore the equation y = mx+b becomes y = 3x+12 which is equivalent to f(x) = 3x+12

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation:

its totaly b

your welcome btw