What is an equation of the line that passes through the point (6,1) and is parallel to the line x + 3y = 15?

x + 3y - 9 = 0

Step-by-step explanation:

(d): x + 3y = 15 -> (d): x + 3y - 15 =0

if (d')║(d)

-> (d'): x + 3y + c = 0

but (d') passes through the point (6;1) => c = -x-3y = -6-3.1 = -9

=> (d'): x + 3y - 9 =0

b.) 160 miles on a 5 gallons car

step-by-step explanation:

240/10=24 miles/gallon

160/5=32 miles/gallon

30/1=30 miles/gallon

168/6= 28 miles/gallon

32 miles/gallon is the most amount, so this is the best.