5x + y = 7
20x + 2 = y

The values of x and y for the given simultaneous equation are;

x = 0.2 and y = 6

We are given 2 simultaneous equations;

5x + y = 7   ---(eq 1)

20x + 2 = y   (eq 2)

Put 20x + 2 for y in eq 1;

5x + 20x + 2 = 7

25x + 2 = 7

25x = 7 - 2

25x = 5

x = 5/25

x = 0.2

Put 0.2 for x in eq 2 to get;

20(0.2) + 2 = y

4 + 2 = y

y = 6

In conclusion, the values of x and y are x = 0.2 and y = 6.

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x=0.2, y=6

Step-by-step explanation:

Since y=20x+2, 5x+y=7 => 5x + (20x +2 ) = 7

                                                     25x + 2 = 7

                                                           25x = 5

                                                                x = 0.2

so y = 20x + 2 = 20* 0.2 +2 = 4 + 2 = 6

so the final solution is

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

d

because parallelagram have all 4 angels the same size dependeing and a rectangle and square are oth parallelogram