O parquinho de uma escola tem o formato de um triângulo. A escola decidiu fazer uma reforma e ampliar o parquinho. Será incluído na área do parquinho o espaço referente ao tracejado da figura abaixo. Sabendo que o ângulo formado pelo novo muro do parquinho e o muro que hoje forma um ângulo de 38° será um ângulo reto, quais são os valores dos dois outros ângulos da parte nova do parquinho que o engenheiro deve considerar para a obra?52º e 38º 64° e 26°
30° e 60°
45° e 45°
60º e 60º

step-by-step explanation:

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hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

answer: 12/52

step-by-step explanation: my reasoning is that there are 12 face cards in a deck and a total of 52 cards in all.