A tortoise challenged a hare to a 100-meter race on a track. The tortoise negotiated a 60-meter head start with the hare. When they passed their respective starting points the hare was running at a constant speed of 3.6 meters per second and the tortoise was crawling at a speed of 0.7 meters per second. (They both maintained these speeds for the entire race.) Our goal is to determine who won the race. Take out a piece of paper and read the above problem statement again. In a couple of sentences, describe how you might determine who won the race. Construct a drawing to represent the 100-meter length of the track. Then place the tortoise and hare's starting points on the track. Define the variable t to represent the number of seconds since the start of the race.

Hare wins the race

Step-by-step explanation:

Length of track = 100 m

Let t represent the number of seconds in completing the race.

Speed of tortoise = 0.7 m/s

Distance covered by tortoise in t seconds = Speed \times time = 0.7t

We are given that The tortoise negotiated a 60-meter head start with the hare.

So, Distance covered by tortoise in t seconds = 60+0.7t

Speed of hare = 3.6 m/s

Distance covered by hare in t seconds = 3.6 t

Now

3.6t = 100

t=27.77

60+0.7t=100

t=57.14

So, Hare took less time

So, Hare wins the race

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

x=0

step-by-step explanation: