Sharel decided to buy a charm bracelet for her mother. She buys 10 charms for the bracelet. How many arrangements of charms are there?

3,628,800 arrangements

Step-by-step explanation:

Permutation has to do with arrangement.

The number of ways to arrange n objects is expressed as:

n! = n(n-1)(n-2) (n-r)!

If Sharel buys 10 charms for the bracelet, the number of ways the charms can be arranged is  10! ways

10! = 10*9*8*7*6*5*4*3*2*1

10! = 720*840*6

10! = 3,628,800 arrangements

Hence there are 3,628,800 arrangements of charms

angle addition postulate

2x=56

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)