Point AAA is at {(6, -6)}(6,−6)left parenthesis, 6, comma, minus, 6, right parenthesis and point CCC is at {(-6,-2)}(−6,−2)left parenthesis, minus, 6, comma, minus, 2, right parenthesis. Find the coordinates of point BBB on \overline{AC} AC start overline, A, C, end overline such that AB=\dfrac34ACAB= 4 3 ACA, B, equals, start fraction, 3, divided by, 4, end fraction, A, C.

B(-3, -3)

Step-by-step explanation:

If a point O(x, y) divides line segment XY in the ratio of n:m and the endpoints of the segment are , the coordinates of O is:

Given that A(6, -6) and C(-6, 2). Pont B is on AC such that:

AB = (3/4)AC

AB/AC = 3/4

Therefore point B divides the line AC in the ratio of 3:1. Let point B be at (x, y), therefore:

Therefore the location of B is at (-3, -3)

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.