The number line shows the distance in meters of two jellyfish, A and B, from a predator located at point X: +

-1.5 0.5

A XB

tet

-2 -1 0 1

+

2

-3

3

Distance (m)

Write an expression using subtraction to find the distance between the two jellyfish. (5 points)

Show your work and solve for the distance using additive inverses. (5 points)

Kindly check explanation

Step-by-step explanation:

According to the number line :

Predator X is located at point 0;

Jellyfish A is located 1.5m to the left of Predator X (at 0) ; Jelly fish A is at - 1.5 m

Jellyfish B is located 0.5m to the right of Predator X (at 0) ; Jellyfish B is at 0.5 m

USING subtraction, the distance between Jellyfish A and B is :

Jellyfish A = - 1.5 m

Jellyfish B = 0.5 m

Distance between A and B = (-1.5 - 0.5)m = - 2.0m

Using Additive inverse :

Number added to - 2.0 to obtain 0;

Let number = x

-2.0 + x = 0

x = 0 + 2.0

x = 2.0 m

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

1 is c

2 is a

3 is a

step-by-step explanation: