Ab-a-b+1 I know it splits into a(b-1)-1(b-1) but can someone explain in words how it becomes (a-1)(b-1) thanks

ab - a - b + 1 = (a - 1)(b - 1)

Step-by-step explanation:

Let us explain factorization by grouping

In the expression of 4 terms ax + by + bx + ay

Take every two terms have a common factor in a bracket

(ax + ay) + (bx + by)

Take the common factor out of the brackets

a(x + y) + b(x + y)

Take the bracket as a common factor

(x + y)(a + b)

Let us do these steps with our question

∵ ab - a - b + 1 is an expression of 4 terms

→ Take ab and a in a bracket, -b and 1 in another bracket

∴ ab - a - b + 1 = (ab - a) + (-b + 1)

→ Take a as a common factor from the 1st bracket and -1 from

   the 2nd bracket

∴ (ab - a) + (-b + 1) = a(b -1) + -1(b - 1)

→ Take the bracket (b - 1) as a common factor

∴ a(b -1) + -1(b - 1) = (b - 1)(a + -1)

∵ (+)(-) = (-)

∴ (b - 1)(a + -1) = (b - 1)(a -1)

→ Change the order of the bracket

∴ (b - 1)(a -1) = (a - 1)(b - 1)

∴ ab - a - b + 1 = (a - 1)(b - 1)

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to

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