Solve the following problem. Be sure to show all the steps (V. E.S. T.) and work in order to receive full credit. The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.

   x+2x+(2x+6)=26

                 x+2x+2x= 26-6

                5x=20

                x=20/5

                x=4

                First number=x=4

                Second number=2x=2(4)=8

                Third number=2x+6=2(4)+6=8+6=14

Step-by-step explanation:

Hope it help. Sorry if its wrong i looked it up and got the answer from some other dude. If u need sum else lmk

answer: yes i agree that you should not put it on/p>

step-by-step explanation: the reason for this is that it wastes other peoples time and also make them fail as well and that is never good.

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.