Suppose it was –5 degrees Celsius at 6:00 a. m. By noon, the temperature had Increased by 11 degrees. What was the temperature at noon?

6

Step-by-step explanation:

11 - -5 = 6

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: