52-inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece, and the third piece is two inches more than seven times the length of the first piece. Find the lengths of the pieces. The lengths of the first, the second, and the third pieces are in, in, and in respectively.

First piece = a = 5 inches

Second piece = b = 10 inches

Third piece = c = 37 inches

Step-by-step explanation:

Let us represent:

First piece = a

Second piece = b

Third piece = c

52-inch piece of steel is cut into three pieces.

a + b + c = 52 inches

The second piece is twice as long as the first piece

= b = 2a

The third piece is two inches more than seven times the length of the first piece.

= c = 2 + 7(a)

Find the lengths of the pieces. The lengths of the first, the second, and the third pieces are in, in, and in respectively.

a + b + c = 52 inches

Substitute 2a for b

2 + 7a for c

a + 2a + 2 + 7a = 52

Collect like terms

10a = 52 - 2

10a = 50

a = 50/10

a = 5 inches.

b = 2a

b = (2 × 5)

b = 10 inches

c = 2 + 7a

= 2 + 7(5)

= 2 + 35

= 37 inches

definitely a. the others have almost all data points on one side of the line.

step-by-step explanation:

sure i'm up for it

step-by-step explanation: