Choose the equation that could be used to find three consecutive integers whose sum is 36. a) n + (n + 2) + (n + 4) = 36
b) n + (n + 1) + (n + 3) = 36
c) n + (n + 1) + (n + 2) = 36
d) n + (n − 1) + (n − 3) = 36

C

Explanation:

n + (n+1) + (n + 2) = 36
n + n + 1 + n + 2 = 36
3n + 3 = 36
3n = 36 - 3
3n = 33
n = 11

Plug n value in the equation:

11 + (11 + 1) + (11 + 2) = 36
11 + 12 + 13 = 36
36 = 36

And 11, 12, 13 are consecutive integers that add up to 36