A baseball diamond is a square with sides 90 ft long. A batter is at bat, with runners at first and second base. At the moment the ball is hit, the runner at first base runs to second base at 25 ft/s. Simultaneously, the runner on second base runs to third base at 15 ft/s. How fast is the distance between these two runners changing 2 s after the ball is hit?

It is changing at -11 ft

Step-by-step explanation:

The distance d is given by

d = √x²+(90-y)²

We have to differentiate

dy/st = 25ft

dx/dt = -15ft

The question says after 2 seconds

Y = 25x2 = 50ft

X = -15x2 = -30ft

Then we calculate rate of change of distance. From the calculations I did, I arrived at

(1/2√900+1600).[900-2000]

= -1100/2x50

= -1100/100

= -11ft

Please check attachment to help you understand the answer better as it is more detailed.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

answer: 177/8

step-by-step explanation: