Given: Sine (A) = StartFraction 5 Over 13 EndFraction, StartFraction pi Over 2 EndFraction < A < Pi and Tangent (B) = negative StartRoot 13 EndRoot, StartFraction pi over 2 EndFraction < B < Pi What is tan(A – B)?

StartFraction 5 + 12 StartRoot 13 EndRoot Over 12 minus 5 StartRoot 13 EndRoot EndFraction
StartFraction 12 minus 5 StartRoot 13 EndRoot Over 5 + 12 StartRoot 13 EndRoot EndFraction
StartFraction 12 + 5 StartRoot 13 EndRoot Over negative 5 + 12 StartRoot 13 EndRoot EndFraction
StartFraction negative 5 + 12 StartRoot 13 EndRoot Over 12 + 5 StartRoot 13 EndRoot EndFraction

D. -5 + 12√13 over 12 + 5√13

Step-by-step explanation:

i think it is 70

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;