John caught 24 trout in bass while on a fishing trip. The total weight of his catch was 137 pounds. The average weight of a trout was 2.5 pounds, and the average weight of a bass was 8 pounds. How many trout and how many bears did he catch?

trouts = 10 and bears = 14

Step-by-step explanation:

Let number of trouts and bears be x and y respectively.

This means that since he caught 24 trout and bass, we have;

x + y = 24 - - - (eq 1)

Now, average weight of trout is 2.5 pounds and average weight of bass is 8 pounds.

Thus;

2.5x + 8y = 137 - - - (eq 2)

From eq(1), let's make x the subject.

Thus;

x = 24 - y

Put 24 - y for x in eq(2)

2.5(24 - y) + 8y = 137

60 - 2.5y + 8y = 137

5.5y + 60 = 137

5.5y = 137 - 60

y = 77/5.5

y = 14

x = 24 - 14

x = 10

Thus, trouts = 10 and bears = 14

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%