Nana has a water purifier that filters \dfrac13 3 1 start fraction, 1, divided by, 3, end of the contaminants each hour. She used it to purify water that had \dfrac12 2 1 start fraction, 1, divided by, 2, end fraction kilogram of contaminants. Write a function that gives the remaining amount of contaminants in kilograms, C(t)C(t)C, left parenthesis, t, right parenthesis, ttt hours after Nana started purifying the water.

(1/2) * (2/3)^t

Step-by-step explanation:

Nana has a water purifier that filters 1/3 of the contaminants each hour. She used it to purify water that had 1/2 kilogram of contaminants.

Write a function that gives the remaining amount of contaminants in kilograms, C(t), t hours after Nana started purifying the water.

C(t)=

The water purifier will filter 1/3 of the current contaminants each hour.

1/3 ÷ 1/2

= 1/3 × 2/1

= 2/3

This means, it willreduce the contaminant into 2/3 of it current mass

To derive the equation,

Multiply the contaminant with 2/3 every hour

(1/2) * (2/3)^t

Where t = hours

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's