Suppose the time it takes a certain printer to print a document is an Exponential random variable with an average time of 15 seconds. You send a document to the printer at 1:00pm, and it is the third document in the queue. What is the probability that your printout will be ready by 1:01pm

0.8046

Step-by-step explanation:

We're asked to calculate the probability that the job will be ready by 1.01 pm

From the question, we can note that the parameter of an Exponential is E(X)= 15

Next, to calculate the third job probability, we will have to use Poisson Distribution with parameter 1/λ

Therefore, E(Y) = 1/15

Then, The third job will be ready for 1:01 pm, and thus E(Y) = 61/15

Therefore, the required probability is

P(X ≥ 3) = 1 - P(X < 3)

= 1 - Poisson(3,4, true)

= 1 - 0.1954

= 0.8046

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.