उक्त समयमा बसले कति दुरी पार गर्दछ ? Abusstarts from rest. If the acceleration of the bus is 0.5m/s, what will be it's
ve ocity at the end of 2 minutes and what distance will it cover
during that time?

The magnitude of the velocity will be 60 m/s.

The distance covered is 3,600 m

Step-by-step explanation:

Constant Acceleration Motion

It's known as a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo is the initial speed, vf the final speed, and t the time, the following relation applies:

The distance traveled by the object is calculated as:

The bus starts from rest, i.e. vo=0, the acceleration is a=0.5 m/s^2. The magnitude of the velocity at t=2 minutes = 120 seconds is:

The magnitude of the velocity will be 60 m/s.

The distance covered during that time is:

x = 3,600 m

The distance covered is 3,600 m

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.