G(x)=2x^2+2x+21
Find g(p+4)

Explanation:

Everywhere you see an x, replace it with p+4, then simplify.

We'll use the FOIL rule to expand out (p+4)^2

So...

g(x) = 2x^2 + 2x + 21

g(x) = 2( x )^2 + 2( x ) + 21

g(p+4) = 2( p+4 )^2 + 2( p+4 ) + 21 every x replaced with p+4

g(p+4) = 2(p^2+8p+16) + 2(p+4)+21 FOIL rule

g(p+4) = 2p^2+16p+32 + 2p+8+21 distribute

g(p+4) = 2p^2 + 18p + 61

no, because the sides are not congruent