Triangle ABC has vertices A (1, 3), B (0,1) andC(4, 0). Under a translation, A’, the imagepoint of A, is located at (4, 4). Under this sametranslation, point C’ is located atA.(7, 1)B.(5, 3)C.(3, 2)D.(1, -1

ion

step-by-step explanation:

ion ion ion ion ion ion ion ion ion ion ion

2,160 π

step-by-step explanation:

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10

1st integer x

2nd integer x+1

3rd integer x+2

4th integer x+3

x+x+1 +x+2+x+3 =74

combine like terms

4x+6 = 74

subtract 6 from each side

4x = 68

x = 17

the integers are 17,18,19,20