Find the width of a rectangular wall if the perimeter is 148 feet and the width is two more than seven times the length.

Step-by-step explanation:

Perimeter of a rectangular wall P = 2L+2W

L is the length of the wall

W is the width

Given

P = 148feet

If the width is two more than seven times the length, this is represented as

W = 7L+2

Substitute W = 7L+2 into the formula above

P = 2L + 2(7L+2)

P = 2L +14L+4

P == 16L+4

148 = 16L+4

16L = 148-4

16L = 144

L = 144/16

L = 9

To get the width

W = 7L+2

W = 7(9)+2

W = 63+2

W = 65feet

Hence the width of the rectangular wall is 65feet

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco

where are the images of the functions i can only see the question you typed.

step-by-step explanation: