A) sin2000x + cos2000x =
1
21999

 The number of solutions to the equation sin (2000x) = 3/7 in the interval [0,2π] is (A) ... 1 answer A sinusoid with amplitude 4 has a minimum value of 5.

1 answer

Step-by-step explanation: : You always have sin2(x)+cos2(x)=1. Now how do sin2(x)+cos2(x) and sin2000(x)+cos2000(x) relate if (sin(x),cos(x))≠(±1,0) and (sin(x),cos(x))≠(0,±1)?

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

nope.   happens to me as well.

-aparri