A box contains 10 tags, numbered 1 through 10, with different numbers on each tag. A second box contains 8 tags, numbered 20 through 27 with a different number on each tag. One tag is drawn at random from each box. What is the expected value of the sum of the numbers on the two selected tags?

29

Step-by-step explanation:

Given that:

Bag 1 : Bag contains 10 tags numbered 1 - 10 with different numbers on each

Bag 2: Another bag with 8 tags numbered from 20 - 27

Two Tags are drawn at random, one from each bag; Expected value of the sum of numbers on the two selected tags :

Expected value = mean of numbers in bag 1 + mean if numbers in bag 2

E(X) = (bag 1 minimum + maximum) / 2 + (bag 2 minimum + maximum) / 2

E(X) = [(1 + 10) / 2] + [(20 + 27) / 2]

E(x) = (11/ 2) + (47/2)

E(x) = 5.5 + 23.5

E(x) = 29

Hence, expected value of sum if numbers from each draw = 29

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5