At New years you decide to join a gym to lose all those calories gained during winter break and youre comparing two different gyms. The first gym, gym A has a 12$ initiation fee and then costs 10$ per month. The second gym , gym B has a 20$ initiation fee and then costs 6$ per month. Create an equation that aims to find when these two gyms will cost the same amount of money

Given:

For gym A, initiation fee = $12 and cost = $10 per month.

For gym B, initiation fee = $20 and cost = $6 per month.

To find:

The equation that aims to find when these two gyms will cost the same amount of money,

Solution:

Let the number of months be x.

Cost function = Initiation fee + (cost)(x)

Cost function for gym A is

Cost function for gym B is

Cost of these two gyms are equal if f(x)=g(x).

Therefore, the required equation is .

On solving this equation, we get

Hence, after 2 months the cost of these two gyms are same.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.