Find the area and perimeter of a rectangle whose sides are √2 + 3 √5 + 2

√10 + 2√2 + 3√5 + 6

2√2 + 2√5 + 10

Step-by-step explanation:

Given parameters:

Dimensions of the rectangle:

         √2 + 3  and √5 + 2

Unknown:

Area and Perimeter of the rectangle  = ?

Solution:

  Area of a rectangle = L x W

   Perimeter of a rectangle = 2 (L + W)

Input the parameters and solve;

     Area = (√2 + 3)(√5 + 2)

             = √10 + 2√2 + 3√5 + 6

   Perimeter of a rectangle  = 2(√2 + 3 + √5 + 2)

                                            = 2√2 + 6 + 2√5 + 4

                                           = 2√2 + 2√5 + 10

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p