The equation of a circle is (x−2)2+(y+6)2=100. Find the equation of a circle that is externally tangent to the given circle and has a center at (14, 3).

(x-14)^2+(y-3)^2=9

Step-by-step explanation:

equation of a circle is (x-h)^2+(y-h)^2=r^2

so center is (14,3) and is tangent externally means

(x-14)^2+(y-3)2=3^2

(x-14)^2+(y-3)^2=9 answer

yes

step-by-step explanation:

yes