Differentiate. y = (x2 - 2x + 6) et O (2x - 2) ex (x2 + 4x + 4) ex O (x2 + 4) ex + 4x + 6

y' = (x² + 4)eˣ

Step-by-step explanation:

Power rule: y' = f'(x)g(x) + f(x)g'(x)

Step 1: Write equation

y = (x² - 2x + 6)eˣ

Step 2: Differentiate

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)